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卷三十二 志第八 曆二

Volume 32 Treatises 8: Calendar 2

Chapter 32 of 明史 · History of Ming
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Chapter 32
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1
Treatise Eight: Calendrics, Part Two.
2
▲ Grand Concordance Calendar Method, Part One (Upper): Origins of the Method.
3
使 祿稿 使
Every calendar rests on its own foundations, and the dynastic history ought record them in full so later generations can investigate. The Taichu calendar's grounding in pitch-pipes and musical regulation and the Dayan's in yarrow-casting are both set forth at length in their respective treatises. The Season Granting Calendar takes observational computation as its foundation, seeking only agreement with the heavens and not forcing alignment with pitch-pipes or hexagram lines. Yet the rationale of its methods, the derivation of its constants, and the full treatment of gnomon shadows and stellar degrees all survive in complete texts. Titles of those works can still be traced in the biographies of Guo Shoujing and Qi Lüqian. The Yuan History excerpts almost nothing; only Li Qian's draft Discourse on Official Emoluments and Calendar Classic remains. Later revisions to the three response rates and tabular constants, the arc-sagitta circle-division methods, and the foundations of the mean, upright, and fixed three differences were all excised and omitted. The compilers' careful thought was thereby lost—a source of regret for those who understand the matter. The present account draws on the Grand Concordance Comprehensive Track, the Draft Calendar, and related works, arranged as follows: first the method's origins, then the tabular constants, then stepwise computation. The origins of the method comprise seven topics: gnomonic surveying; arc-sagitta circle division; ecliptic and equatorial inner and outer degrees; the white path's crossing circuit; the mean, upright, and fixed three differences for the sun, moon, and five planets; and terrestrial parallax with clepsydra graduations.
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▲ Gnomonic Surveying.
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At Beijing a four-zhang gnomon was set up; at true noon on the winter solstice its shadow measured seven zhang, nine chi, eight cun, and five fen. The simplified armillary then gave the Sun's south declination above the horizon as 26°46′30″, taken as the half-arc back. The sagitta came to 5°91′30″. Take the celestial half-diameter and subtract the sagitta; the remainder, 54°96′, is the leg—the local colatitude under the subsolar point. Applying the chord–leg separation to obtain the other leg yielded 26°07′66″ as the half-arc chord of the Sun's altitude above the horizon.
6
At Beijing a four-zhang gnomon was set up; at true noon on the summer solstice its shadow measured one zhang, one chi, seven cun, and one fen. The simplified armillary then gave the Sun's south declination above the horizon as 74°26′30″, taken as the half-arc back. The sagitta came to 43°74′, slightly less. Take the celestial half-diameter and subtract the sagitta; the remainder, 17°13′25″, is the leg—the local distance from the subsolar point. Applying the leg–chord separation to obtain the base leg yielded 58°45′30″ as the half-arc chord of the Sun's altitude above the horizon.
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Adding the two solstice altitudes gives 100°73′; halving yields 50°36′30″ as Beijing's equatorial altitude above the horizon. Subtracting the equatorial altitude from a quadrant of the celestial circuit leaves 40°94′93″75 as Beijing's polar altitude above the horizon.
8
▲ Arc-Sagitta Circle Division.
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The celestial diameter is fixed at 121°75′, slightly less. The 'slightly less' fraction is dropped in use. The half-diameter is 60°87′30″. This value also serves as the great chord linking ecliptic and equator. At the solstices the inner and outer half-arc backs on the ecliptic and equator are 24°. Observed values are used as rounded integers. At the solstices the ecliptic–equatorial arc sagitta is 4°84′12″. The great altitude leg of the ecliptic–equatorial triangle is 23°80′70″. The great base leg of the ecliptic–equatorial triangle is 56°02′68″. This is the half-diameter minus the sagitta.
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Method for finding the sagitta by circle division: square the half-arc back to obtain the half-arc-back power; square the celestial diameter to obtain the upper excess. Multiply the upper excess by the half-arc-back power to form the positive product. Multiply the upper excess by the diameter to form the augmenting companion square. Double the half-arc back and multiply by the diameter to form the lower excess. Multiply the first trial quotient by the upper excess, subtract from the augmenting companion square, and take the remainder as the companion square. Square the first trial quotient, subtract from the lower excess, and multiply the remainder by the first trial quotient to obtain the companion excess. Add the companion square and companion excess to form the lower divisor. Multiply the lower divisor by the first trial quotient and subtract from the positive product; if the product is insufficient, adjust the first quotient. If a remainder remains, continue successive quotient divisions. Double the first quotient, add the second quotient, multiply by the upper excess, subtract from the augmenting companion square, and take the remainder as the companion square. Square the sum of the first and second quotients and also square the first quotient alone; subtract both from the lower excess; multiply the remainder by twice the first quotient plus the second quotient to obtain the companion excess. Add the companion square and companion excess to form the lower divisor. Multiply the lower divisor by the second quotient, subtract from the remaining product, and thereby fix the second quotient. If a remainder still remains, continue dividing by the same procedure; each quotient obtained contributes to the sagitta in degrees. The ecliptic and equator employ the same procedure.
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Example: to find the sagitta for a half-arc back of one degree. The procedure runs: square a half-arc back of one degree to obtain 1° as the half-arc power. Square the celestial diameter 121° slightly more to obtain 14,823°06′25″ as the upper excess. Multiply the upper excess by the half-arc power to obtain 14,823°06′25″ as the positive product. Multiply the upper excess again by the diameter to obtain 1,804,707°85′93″75 as the augmenting companion square. Double the one-degree half-arc back to obtain 2°; multiply by the diameter to obtain 243°50′ as the lower excess. First trial quotient: 80″. Multiply the first quotient 80″ by the upper excess 14,823°0625 to obtain 118°5845; subtract from the augmenting companion square 1,804,707°859375; the remainder 1,804,589°274875 is the companion square. Square the first quotient 80″ to obtain 64 micro-units; subtract from the lower-excess remainder 243°49936. Multiply again by 80″ to obtain 1°947999488 as the companion excess. Add companion excess and companion square to obtain 1,804,591°222874488 as the lower divisor. Multiply the lower divisor by the first quotient to obtain 14,436°729782995904; subtract from the positive product; the remainder is 386°332717004096. Second trial quotient: 2″. Double the first quotient 80″ to obtain 1′60″. Add the second quotient 2″ to obtain 82″; multiply by the upper excess 14,823°0625 to obtain 240°1336125; subtract from the augmenting companion square; the remainder 1,804,467°257625 is the companion square. Square the combined first and second quotient 82″ to obtain 67 micro-units. Add the square of the first quotient alone (80″) to obtain 1″31μ; subtract from the lower excess; the remainder is 243°499869. Multiply by the 1′62″ obtained above to get 3°9446978778 as the companion excess. Add companion excess and companion square to obtain 1,804,471°670460378 as the lower divisor. Multiply the lower divisor by the second quotient to obtain 360°89433409207556; subtract from the remaining product; the remainder is 25°43838291202044. Fractions below one second are discarded; the same rule applies below.
12
In all, the sagitta obtained is 82″; for other arc lengths apply the same procedure to obtain the sagitta—the foundation for converting between ecliptic and equator and for their inner and outer degrees. The full tables appear below.
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▲ Ecliptic–Equatorial Difference.
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Method for finding the accumulated equatorial degree corresponding to each ecliptic degree. Take the celestial half-diameter and subtract the ecliptic sagitta; the remainder is the small ecliptic–equatorial chord. Set the small chord and multiply by the great base leg of the ecliptic–equatorial triangle (given under circle division) to form the product. Use the great chord—that is, the half-diameter—as divisor. Divide the product by the divisor to obtain the small base leg of the ecliptic–equatorial triangle. Square the ecliptic sagitta for the product, divide by the full celestial diameter, and obtain the ecliptic half-back chord correction. Subtract this correction from the accumulated ecliptic degree to obtain the ecliptic half-arc back. The remainder is the ecliptic half-arc chord. Square the ecliptic half-arc chord for the leg power and the small base leg for the altitude power; add the two powers and take the square root to obtain the small equatorial chord. Multiply the ecliptic half-arc chord by the half-diameter (the great equatorial chord) for the product and divide by the small equatorial chord to obtain the equatorial half-arc chord. Take the small base leg as the equatorial transverse small altitude, multiply by the half-diameter for the product, divide by the small equatorial chord to obtain the transverse great altitude; subtract from the half-diameter; the remainder is the equatorial transverse arc sagitta. Square the transverse arc sagitta, divide by the full diameter, and obtain the equatorial half-back chord correction. Add this correction to the equatorial half-arc to obtain the accumulated equatorial degree.
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Example: for an ecliptic half-arc back of one degree, find the accumulated equatorial degree. The procedure runs: "Set the half-diameter at 60°87′50″—this is the great ecliptic–equatorial chord. Subtract the ecliptic sagitta 82″; the remainder 60°8668 is the small ecliptic–equatorial chord. Multiply the small chord by the great base leg 56°0268 to obtain 3410°17203024 as product; divide by the great chord 60°875; the quotient is 56°0192 as the small base leg. This value also serves as the small equatorial altitude leg. Square the sagitta 82″ to obtain 67 micro-units; divide by the full diameter 121°75 to obtain 55 fine units as the ecliptic half-back chord correction. Set the ecliptic half-arc chord at 1°; subtract the half-back chord correction; because the correction lies below the micro-unit it is not subtracted—take 1° directly as the half-arc chord. Square the ecliptic half-arc chord 1° to obtain 1° as the leg power. Square the small base leg 56°0192 to obtain 3138°15076864 as the altitude power. Add the two powers to obtain 3139°15076864 as the chord product; take the square root to obtain 56°0281 as the small equatorial chord. Multiply the ecliptic half-arc chord 1° by the half-diameter (the great equatorial chord) to obtain 60°875 as product; divide by the small equatorial chord 56°0281 to obtain 1°0865 as the equatorial half-arc chord. Set the small base leg at 56°0192; it also serves as the small equatorial altitude leg. Multiplying by the equatorial great-chord semidiameter of 60°87′50″ yields 3410.1688 as the dividend; dividing by the equatorial small chord gives 60°86′53″ as the equatorial transverse great leg. Take the semidiameter of 60°87′50″ and subtract the equatorial great leg of 60°86′53″; the remainder of 97″ is the equatorial transverse arc-versine. Square the equatorial transverse arc-versine of 97″ to get 94 wei 09; dividing by the full diameter yields 70 xian as the equatorial back-chord correction. Add the equatorial back-chord correction to the equatorial half-arc chord of 1°08′65″ to obtain the equatorial accumulated degree; since the correction falls below the wei, it is not added—the half-arc chord itself serves as the accumulated degree.
16
The equatorial accumulated degree thus obtained is 1°08′65″. For each remaining degree, repeat the procedure to find the equatorial accumulation under each ecliptic degree; the difference between the two values is the ecliptic–equator correction, carried through to the later rate tables. For the fractional parts, to derive ecliptic from equatorial degrees, invert the same procedure; the quantities are identical.
17
▲ Ecliptic–equator mutual arc-versine rates: ready-made tables (upper section)
18
[Table omitted.]
19
▲ Ecliptic–equator mutual arc-versine rates: ready-made tables (lower section)
20
[Table omitted.]
21
Commentary: Guo Shoujing established five methods; ecliptic difference is one of them, and these are its fundamental rates. The older method relied on subtracting and multiplying by 101 degrees. The Season Granting calendar established its procedure through right-triangle, arc-versine, circle–square, and oblique–rectilinear relations to derive the numerical differences—conforming to the armillary model and finer than antiquity. Yet the Calendar Classic of the Zhiyuan reign records only an abridgment and also mistakenly treated ecliptic versine degrees as accumulated difference and ecliptic versine difference as rate—here corrected.
22
▲ Diagram: circle-cutting and arc-versine
23
Whenever a sphere is bisected through its center, a plane circle results. Cut any segment of the plane circle and an arc-versine figure is formed, each with arc-back, arc-chord, and versine. Bisect the arc-versine figure and one has half arc-back, half arc-chord, and versine. From the chord–versine right triangle: the half arc-chord is the leg, the semidiameter minus the versine is the base, and the semidiameter is the hypotenuse. Within the legs a smaller right triangle arises, with small leg, small base, and small hypotenuse, so large and small quantities and plane and lateral relations can be interconverted—the spherical principle is thereby rendered precise.
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The plane circle is the equator; the oblique circle is the ecliptic. From the ecliptic–equator separation at the two solstices arises the great right triangle. From the ecliptic–equator separation at each degree arises the small right triangle.
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The outer great circle is the equator. Viewed from the north pole in the plane, the ecliptic lies inside the equator; each equatorial degree has its half arc-chord, yielding the great base. Each also has its corresponding ecliptic half arc-chord, yielding the small right triangle. The two can be derived from each other.
26
Commentary: Earlier histories carried no diagrams, yet ready-made tables are themselves a kind of diagram. The leg–hypotenuse method for cutting arcs and versines is in fact the foundation of calendrical computation. Without a diagram it cannot be made clear; therefore a few essentials are preserved here.
27
▲ Ecliptic and equator: degrees within and without
28
Procedure for deriving, at each ecliptic degree, the distance within or without the equator and the distance from the pole. Take the semidiameter and subtract the equatorial small chord; the remainder is the equatorial double-chord difference. This value also serves as the ecliptic–equator small arc-versine, as the inner-and-outer versine, and as the base–hypotenuse difference. Subtract the ecliptic versine degree from the semidiameter (within or without as the case requires); the remainder is the ecliptic–equator small chord. Multiply it by the solstitial inner-and-outer half arc-chord as dividend and divide by the ecliptic–equator great chord (the semidiameter). The quotient is the ecliptic–equator small arc-chord. This is the ecliptic–equator inner-and-outer half arc-chord, and also the ecliptic–equator small leg. Square the ecliptic–equator small arc-versine to obtain the equatorial double-chord difference. Divide by the full diameter to obtain the half back-chord correction. Add the correction to the ecliptic–equator small arc-chord to obtain the small half arc-back—that is, the ecliptic–equator inner-and-outer degree. Take the ecliptic–equator inner-and-outer degree: add the quadrant limit where it falls within the waxing-initial and waning-final limit, subtract where within the waning-initial and waxing-final limit—in each case yielding the Sun's distance from the north pole in degrees and minutes.
29
Example: after the winter solstice at 44°, find the Sun's distance within or without the equator and from the pole. The procedure says: "Set the semidiameter at 60°87′30″. Subtract the equatorial small chord at ecliptic 44° (58°35′69″); the remainder of 2°51′81″ is the ecliptic–equator small arc-versine. That is, the inner-and-outer versine. Set the semidiameter at 60°87′50″. Subtract the ecliptic versine at 44° (16°56′82″); the remainder of 44°30′68″ is the ecliptic–equator small chord. Multiply the ecliptic–equator small chord by the solstitial inner-and-outer half arc-chord of 23°71′ to obtain 1050°51′4238 as dividend; dividing by the ecliptic–equator great chord of 60°87′50″ yields 17°25′19″ as the ecliptic–equator small arc-chord. That is, the inner-and-outer half arc-chord. Square the ecliptic–equator small arc-versine of 2°51′81″ and divide by the full diameter of 121°75′ to obtain a back-chord correction of 5′21″; adding this to the small arc-chord of 17°25′69″ gives 17°30′89″ as the Sun's equatorial inner-and-outer distance at 44° from the solstice. Take the quadrant limit of 91°31′43″75 wei and add the inner-and-outer degree of 17°30′89″, obtaining 108°62′32″75 wei as the Sun's distance from the north pole at 44° after the winter solstice.
30
▲ Ready-made tables: for each ecliptic degree, distance within or without the equator and from the pole
31
[Table omitted.]
32
▲ White path: nodal period
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Procedure for deriving the white-path equatorial node and its polar distance from the ecliptic–equator node. The procedure says: "Take the empirically measured white path's separation from the ecliptic at 6° as semidiameter arc-chord, also as great-circle arc-versine, and also as base–hypotenuse difference. Square the semidiameter of 60°75″ to obtain 3705°765625; dividing by the 6° versine yields 617°63′ as the base–hypotenuse sum; adding the 6° versine gives 623°63′ as the great-circle diameter. By the prescribed method the contained breadth of 5°70′ is obtained, which also serves as the small leg. Take the solstitial entry-and-exit half arc-chord of 23°71′ as the great leg. Divide the great base of 56°06′50″ by the great leg as divisor, obtaining 2°37′ rounded to the nearest degree as the degree difference. Multiply the degree difference by the small leg to obtain the small base of 13°47′82″ as the contained half-length. Take the semidiameter of 60°87′50″ as great hypotenuse and multiply by the small leg of 5°70′; dividing by the great leg of 23°71′ yields 14°63′ as small chord, and also as the half arc-chord between the white-path equatorial node and the ecliptic–equator node. By the prescribed method the half arc-back of 14°66′ is obtained as the polar distance of the white-path equatorial node from the ecliptic–equator node.
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